TIMESTAMP Functions. DATE_FORMAT () Format date as specified. lastModified and w. But your query is giving the last date of previous month. Currently I am only returning 1. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters):. PRINT DATEDIFF(Day, 2010-01-20, 2010-01-01) RETURN 19 Which is correct. 2. *Subtract the two date values, divide by (60 seconds * 60 minutes *. If you enter a negative parameter, the system subtracts the specified days, months, or years. I have a request to build a set of worksheets that accept an intial parameter - Start Date in the format MMM YYYY. That prevents. Push out all due dates by one week. Otherwise, the resulting date has the same day component as. Date 2: 1st Feb 2011. lastModified - w. MySQLには MONTH 機能がありますが、Oracleにはありません。 存在しない関数 DATEDIFF が無効なIDであるのと 同じ理由。 ORA-00904の解決策は、 EXTRACTという名前の正しいOracle関数 を呼び出して、列の月の値を取得することです。Use DATEADD and DATEDIFF() function together in SQL query. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. Once you have the date difference, you can use simple techniques to express the difference in days, hours, minutes or seconds. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. In addition, with DATEDIFF () the column is an argument to the function. DECLARE @date datetime2 = '2021-01-07 14:36:17. Compare dates problems. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 DateDiff is not a function that exists in Oracle. DatePart. If you subtract from one date other you will get a count of days between this two dates. I tried this selectThat said, you can use the following to determine if the date falls on a weekend: SELECT DATENAME (dw,GETDATE ()) -- Friday SELECT DATEPART (dw,GETDATE ()) -- 6. The add_days variable can be negative. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. Then, we need a 2-digit month string. 2. LeapYear Returns one (1) if the specified year is. 2) format. 15 between 2 values that are 1 year, 1 month and 15 days apart. The Question asked for "6 months from the system date". StartDate) AND. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. MONTHS_BETWEEN gives the number of whole months between the 2 dates, and calculates the fractional part as the remainder in days divided by 31. Dates are always a joy to work with in any programming language, SQL not excluded. sql. DAYS function. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. lastModified and w. Commonly used datepart units include month or second. Use a built-in function to “move”. Then Oracle will not use an index on the date_column and would need a separate function-based index on either TRUNC(date_column) or TO_CHAR(date_column, 'DD-MM-YYYY'). Using datediff in oracle. The Stored Procedure accepts two inputs - A start date and end date of the date range desired by the user. Table 9. For example: print &order_date () edit 'Month dd, YYYY'. Here is an example that uses date functions. DateAdd. * , dd. Voila! You've the the last day of the month containing your reference point in time. Start date will. Expressions can contain only one hint. All functions can be used in both the load script and in chart expressions. Funciones comúnmente utilizadas de Oracle: DateDiff devuelve una función personalizada para el intervalo entre dos fechas (Por supuesto, hay otros métodos para lograr, en ORACLE los tipos de fechas se pueden comparar directamente, y finalmente dar ejemplos de métodos). The week (wk, ww) datepart reflects changes made to SET DATEFIRST. Usage Notes¶. mm is a two digits of minute (00 through 59). , for the Oracle database: sale_date >= TRUNC (sysdate) AND sale_date < TRUNC (sysdate + INTERVAL '1' DAY) Another common obfuscation is to compare dates as strings as shown in the following PostgreSQL example:The trick here is to get the first day of the next month which will always be 01-NextMonth-Year. The Oracle NEXT_DAY() function returns the date of the first weekday specified by day name that is later than a date. Improve this answer. DateGroup. 0: EF. I have to get the date from the system and calculate the date difference in days. Oracle equivalent to SQL Server/Sybase DateDiff. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. Month and day of the year don’t appear to be factored into the equation. Functions that return the current date or time each are evaluated only once per query at the start of query execution. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. This is going to be short:. February 28 and March 31), the fractional portion is zero, even if the days of the month are not the same. It uses month boundaries as calculating the difference in months, with each change in calendar month adding one to the answer. 3. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. NEXT_DAY(date,weekday) Code language: SQL (Structured Query Language) (sql) Arguments. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. 'month' or month). subtract and give the difference in number of. 8. It is the unit in which the DATEDIFF() function returns the difference between a start date and an end date e. This function is not sensitive to the NLS_CALENDAR session parameter. Previous SQL Server Functions Next . HQL Date format in Oracle / PostgreSQL: select TO_CHAR. substr (to_char (to_date ('01-02-2018','mm-dd-yyyy'), <NLS_DATE_FORMAT>),4,3) The usual default value (for English-language versions of. 2 Answers Sorted by: 0 The best thing to do in this case is to use Oracle's MONTHS_BETWEEN () function. Sorted by: 55. Currently I am only returning 1. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. DATE_FROM_UNIX_DATE. (INTCK returns a negative value whenever the first date is. 利用日期间的加减运算. DATE_SUB () Subtract a time value (interval) from a date. datediff('MONTH', pr. This function is not sensitive to the NLS_CALENDAR session parameter. 1. The days are in two different, adjacent months, so the answer is 1 month difference. The format argument is optional. Fractions are allowed; you can add 2. ( See. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. g. Syntax¶ MONTHS. For Oracle: Last 6 Months. I see that marked final solution is not correct always. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. And here is a link to a pretty good function to mirror DATEADD in DB2. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. NEW_TIME (date, timezone1, timezone2) Timestamp. Goal. Modified 1 year, 3 months ago. I have a creation date column in the table. Modified 3 months ago. date_from, evnt. 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. 25)) AS `numberofemployees`. We would like to show you a description here but the site won’t allow us. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. Third, the more verbose method. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. user637544 Jun 1 2009 — edited Jun 1 2009. DATE_SUB. ) that are available and in this tutorial, we look at how to use the DATEADD function in SQL queries, stored procedures, T-SQL scripts,. Another example is to get the month of. If you want an integer. Get Number of Months Between 2 Dates. 005479 (1 year + 2/365 years). DATE_DIFF = 1. The second method uses an extract function to obtain the years, months, and days separately. Kindly tell me how to calculate age as in years month days. Discussion: To calculate the difference between the timestamps in Oracle, simply subtract the start timestamp from the end timestamp (here: arrival - departure ). Last 3 Months. The second method uses an extract function to obtain the years, months, and days separately. Modified 2 years, 9 months ago. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. Oracle SQL time difference in HH:MM:SS. g. Fractions are allowed; you can add 2. Viewed 32k times. Move the start date to the next Monday, then add the calculated weeks. If they are identical down to the second then, presumably, returning 0 is the right. DATEDIFF (day/month/year, <start_date>, <end_date>);AT TIME ZONE. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. However, The problem is different number of records because DATEDIFF(month,a,b)<=4 in SQL Server returns only the month difference whereas months_between(a,b)<=4 in oracle returns the. Arguments. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. from a date time value. If you want an integer number of days. Functions. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. – user330315. CurrentMember), Today(), DP_MONTH ) < 6 ) ON ROWS FROM Mysamp. 3. We need to subtract a second from first day of current month. 3. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. sql-server-2008. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. 00. 9. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. 2258064516. DATEADD(datepart,number,date) The DATEPART() function is used to return a single part of a date/time, such as year, month, day, hour, minute, etc. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. This function is used to get the timestamp value from the specified character string. datediff isn't a function in Oracle. 3 Answers. Sorted by: 3. datepart: It is the part of the date like day, month, year, week, etc. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. Adds the specified number of months to a date or timestamp. . 天：. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. This gets the year difference between the birth date and the current date. Tip 032: Summary of Date Functions. We are in the process of migrating to a PostgreSQL SDE and with the same feature class the query no. If date1 is later than date2 , then the result is positive. for oracle: months_between. 0. Add a comment. ADD_MONTHS. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. DATEDIFF is wrong. When you subtract two dates in Oracle, you get the number of days between the two values. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. date_open END. Snowflake doesn't offer a function that does that. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. DD is a two-digit day of the month (01 through 31). Share. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. For example, adding three months or 12 days to a starting date. Returns the <date> with the specified number <interval> added to the specified <date_part> of that date. DiffMonths Returns the difference in months between two dates. 000 which is the start of the. Last 3 Months. Converting Valid Character Strings to Dates, Times, or Timestamps. Improve this answer. Share. I need to calculate the difference between two dates in Oracle sql and show it in the following format: 'x years y months z days'. Two dates to calculate the number of days between. Date > T1. 997 to avoid that. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. Please refer the below examples and kindly let me know your ideas. SYSTIMESTAMP). Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. select trunc (months_between (:end_date,. * FROM #HRAL h INNER JOIN #LAZY_DATE_DIM dd ON dd. 005479 0. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. mysql> SELECT. Date manipulation is a common scenario when retrieving or storing data in a Microsoft SQL Server database. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. TZD is a time zone designator ( Z, + / - hh: mm or + / - hhmm ). Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. This function adds a specified number of days, months, and years to a given date. It is a function of SQL server. g. measure is the name of a measure column. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. January 30, 2004 - 7:26 pm UTC. g. Asked 1 year, 8 months ago. Concatenates a date to a time on either side of the + symbol and returns a TIMESTAMP or TIMESTAMPTZ. The values to compare. 8. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. The first number you see is the number of whole days that passed from departure to arrival. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0) returns the beginning of next month. They both do very different things. Here's how it does this: First the DATE function creates the date, 5/1/2016. You could also use the add_months function: AND s. Tdy. 0. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. where (year(getdate())-year(birthDate)) = 17. enddate,e3. object_id ) AS nbr FROM sys. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Improve this answer. As we can see in the screen shot the query displays the months between the two dates. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. I have a table where PurchasedDate is maintained. However, The. From the documentation: date_part (): The date_part function is modeled on the traditional Ingres equivalent to the SQL-standard function extract:Date/time functions. The SQL code is "where fac. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. I want to calculate the current Age from Date of Birth in my Oracle function. Returns 'Oracle Database 10g Enterprise Edition Release 10. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. The math is 100% accurate for dates within a couple of hundred years or so. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. The following shows the syntax of the DATEPART() function: DATEPART ( date_part , input_date ) Code language: SQL (Structured Query Language) (sql) The DATEPART() takes two arguments: date_part is the part of a date to be extracted. , SYSDATE - pr. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. I would like to select 1 if current date falls between 2 dates through Oracle SQL. you can check against last 90 days. 14. 2188940092 Example 2 Date 1: 10th March 2011 Date 2: 1st Feb 2011 MONTHS_BETWEEN = 1. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. So then in DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0) that same number of months is added back to 1900-01-01 to get the start of the current month. Must be one of the values listed in Supported Date and Time Parts (e. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. CASE WHEN a. How best can this be written? I need to use this in a where clause on DI Studio. (You can also subtract fractions of days, but that might be outside the scope of this answer. select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. Syntax. CODE = 'CONTACT_CLIENT' THEN a. Using the standard EMP and DEPT tables, for example. 032258 the problem lies in the fact that a month is a nebulous thing - it is not a precise number of days. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. Syntax. Instead of: datediff ('QUARTER', pr. The DATEDIFF() function returns the number of days between two date values. lastModified - w. Select name,surname,datediff(YY,birthDate,getdate()) as age from students order by age. Oracle doesn't have a DATEDIFF() function. What I am using is (Today-Dob)/30/12, but this is not accurate as some months have 31 days. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. Calculates the difference in days between the two dates. SHOW_DAY is an alias to store the day. Hi Ive been having an issue with getting the correct difference in a date from the current month not including the day. We will use the below date for the examples. join our newsletter and get access to exclusive content every month. In addition, with DATEDIFF () the column is an argument to the function. DATE_DIFF = 1. Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. If date1 and date2 are either the same days of the month or both last days of months, then the result is always an integer. I can mention four important functions of MS SQL Server that can be very useful: 1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):. sql-server. 2. It isn't exact but may work for you. i. PostgreSQL. (You can also subtract fractions of days, but that might be outside the scope of this answer. . 0 months apart:Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. Two dates to calculate the number of days between. The following illustrates the syntax of the DATEPART. 0. ) and rest are two dates which you want to compare. Notice that the first row has a difference of 1. As per the methodology used in this date calculator, a week starts on 'Monday' and ends on 'Sunday'. End Function. February 28 and March 28) and when the days of the month are the last day of the month (e. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. The result is formatted according to the Format parameter. The DATEDIFF() function returns the difference between two dates. Multiply the result of step 1 by 12 to transform it to months 3. 7 Reference Manual :: 12. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. The result is formatted according to the Format parameter. Learn more about Teams dp_monthは、入力日付を取得する月間の距離を返します。 (2006年10月) - 2005年6月= 16) dp_weekは、入力日付を取得する週間の距離を返します。 各標準カレンダ週は日曜日に始まり、7日にまたがるように定義されています。 (2006年10月10日 - 2005年6月14日= 69) Converting a raw number of days into a number of weeks and days is pretty simple. SQR for PeopleSoft provides an extensive set of date edit masks. for extended XSL functions. The DATEADD() function adds or subtracts a specified time interval from a date. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. Was this tutorial helpful? Previously Oracle ROW_NUMBER Up Next Oracle ADD_MONTHS This tutorial provides you with the most commonly used Oracle date. here i am trying get the month differences between two. In effect, substr (to_date ('01-02-2018','mm-dd-yyyy'),4,3) is the same as. We would like to show you a description here but the site won’t allow us. If date1 is earlier than date2 , then the result is negative. 1. ROUND (TO_NUMBER (END_DATE - START_DATE) * 24) 分钟：. Parameter Description; date1, date2: Required. PostgreSQL. startdate)-1 as [Datediff] from #temp e1 join #temp e3. sql. Follow edited Oct 19, 2016 at 9:44. Viewed 417k times 57 I would. Example-3: List the name and surname of students whose age 17. SYSDATE is already a date. Recall that earlier I mentioned that in my example I. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. Oracle PeopleSoft Tips and Tricks. Returns a date string or the current date. Constructs a DATE value. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. 1. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. Interprets an INT64 expression as the number of days since 1970-01-01. Modified 8 years ago. If date1 is earlier than date2, then the result is negative. The number is the number of seconds elapsed since midnight, January 1, 1970. JohnD JohnD. One truncates a date to the precision specified (kind of like rounding, in a way) and the other just returns a particular part of a datetime. Try SELECT FORMAT (DATEADD (month, -1, GETDATE ()),'MM/yyyy'); It will give you previous month and the year. declare @datetime datetime; set @datetime = getdate (); select @datetime; select dateadd (year,datediff (year,0,@datetime),0); select dateadd (month,datediff (month,0,@datetime),0); select dateadd (day,datediff. Option 1. g. Start learning SQL now ». * 12 + (Extract(Month From CDate(EndDate)) - Extract(Month. then if day/month of dob is less than. DatePart. Query all. For both ADD_MONTHS and DATEADD, if the result month has fewer days than the original day, the result day of the month is the last day of the result month. 0 and later Information in this document applies to any platform. select add_months ( date'2021-01-01', ( level - 1 ) * 12 ) as yr_add_months, date'2021-01-01' + numtoyminterval ( level - 1, 'year' ) yr_interval from dual connect by. 997 All results I use in BETWEEN operator, therefore last 'day' should include last millisecond of the very day. ). So I am porting many SQL Procedures to Oracle. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. 5 days to a given date. Just to make the warning explicit to everyone looking at this answer: the subquery SELECT ROW_NUMBER() OVER ( ORDER BY c. This is so as for the ease of use later for php. g. MONTHS_BETWEEN returns number of months between dates date1 and date2. To break the diff between 2 dates into days, hours, minutes, sec -- you can use the following: Dy gives you number of days between 2 dates (partial days discarded). Of course, if you need days instead of months, you can simply subtract one date from another, e.